A car travels first 10km in 20 minutes and another 10 km in 30 minutes.what is the average speed of the car in m/s?
Answers
Answered by
18
Total distance = 10 km +10 km
=20 km
= 20000 m
Total time = 20 min + 30 min
= 50 min
=( 50 * 60 ) s
=3000 s
Average speed = (20000 / 3000)m/s
= 6.66 m/s(approx)
=20 km
= 20000 m
Total time = 20 min + 30 min
= 50 min
=( 50 * 60 ) s
=3000 s
Average speed = (20000 / 3000)m/s
= 6.66 m/s(approx)
Answered by
8
So let's find the answer
10km=10×1000
=10000m
10km=10×1000
=10000m
20mins=20×60
=1200sec
30mins=30×60
=1800sec
Average speed=Distance covered/time taken
So,10000m+10000m/1200sec+1800sec
=20000m/3000sec
=20000/3000
=6.67m/s
I hope you got answer
10km=10×1000
=10000m
10km=10×1000
=10000m
20mins=20×60
=1200sec
30mins=30×60
=1800sec
Average speed=Distance covered/time taken
So,10000m+10000m/1200sec+1800sec
=20000m/3000sec
=20000/3000
=6.67m/s
I hope you got answer
Similar questions