Two poles of lengths 10 ft. and 15 ft. are set up vertically with their bases on horizontal ground 12 ft apart. Find the distance between the tops of the poles.
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Answered by
8
The required answer is 13ft
It is because obviously 15 ft pole is bigger and bigger by 5 ft
And the distance between the poles will be the sam throughout the length of 10 ft pole as then poles are vertically placed
So we get perpendicular as 5ft and base as 12 ft
We needed to calculate the hypotenuse which we got through pythagoras theorem
If u draw a diagram , it would be easier
Thank u★★★
#ckc
It is because obviously 15 ft pole is bigger and bigger by 5 ft
And the distance between the poles will be the sam throughout the length of 10 ft pole as then poles are vertically placed
So we get perpendicular as 5ft and base as 12 ft
We needed to calculate the hypotenuse which we got through pythagoras theorem
If u draw a diagram , it would be easier
Thank u★★★
#ckc
Answered by
10
AE =BD=12ft
CE=5ft
BY PYTAGORES THEOREM
(Hy)^2=(h)^2+(b)^2
(Hy)^2=144+25=169
Therefore Hypotenusr=13
Or AC=13
CE=5ft
BY PYTAGORES THEOREM
(Hy)^2=(h)^2+(b)^2
(Hy)^2=144+25=169
Therefore Hypotenusr=13
Or AC=13
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