Question

A car travels first 40km in 1 hour, next 40km in 1.5 hours and last 40km of the journey in 0.5 hours. Calculate the average speed of the car during the entire journey. 1t

Answer 1

▶ Solution :

Given :

▪ A car travels first 40km in 1h, next 40km in 1.5h and last 40km of the journey in 0.5h

To Find :

▪ Average speed of the car during the entire journey.

Concept :

✒ Average speed is defined as the ratio of total distance travelled to the total time taken.

✒ It is a scalar quantity.

✒ It has only magnitude.

Mathematically,

☞ Vav = (Total distance travelled) ÷ (Total time taken)

Calculation :

→ Vav = (40+40+40)/(1+1.5+0.5)

→ Vav = 120/3

→ Vav = 40kmph

Answer 2

Given :-

A car travels 40 km in 1 hour

Next 40 km in 1.5hours and last 40km in 0.5 hours

To find :-

The Average speed of car during entire journey

$\bigstar{\boxed{\sf{Average \ speed = \dfrac{Total \ Distance\ covered }{Total \ time \ taken }}}}$

Average Speed :- It is defined as the Total distance travelled by a body in definite interval of time.

It has no direction only magnitude

or

The total distance covered divided by total time taken to cover this distance

• Now the Average speed of car

$\dashrightarrow\sf Average \ speed =\dfrac{D_1+D_2+D_3}{T_1+T_2+T_3}\\ \\ \dashrightarrow\sf Average \ speed =\dfrac{40+40+40}{1+1.5+0.5}\\ \\ \dashrightarrow\sf Average \ speed =\cancel{\dfrac{120}{3}}\\ \\ \dashrightarrow\sf Average \ speed = 40km/h$

$\underline{\textsf{\textbf{\dag \ \ Average \ speed \ of \ car =40km/h}}}$