A car travels first 50 km with a constant speed of 30 km/h and next 40 km with a constant speed of 60 km/h . Caculate the average speed .
Answers
Answered by
28
distance 1 = 50km
speed1 = 30km/h
time taken = distance /speed
= 50/30= 5/3 h
distance 2 = 40km
speed 2 = 60km/h
time taken = distance / time
= 40/60
= 2/3 h
average speed= total distance/total time taken
= (50+ 40)÷ (5/3)+ (2/3)
= 90 ÷ (7/3)
= 270/7
= 38.67km/h
speed1 = 30km/h
time taken = distance /speed
= 50/30= 5/3 h
distance 2 = 40km
speed 2 = 60km/h
time taken = distance / time
= 40/60
= 2/3 h
average speed= total distance/total time taken
= (50+ 40)÷ (5/3)+ (2/3)
= 90 ÷ (7/3)
= 270/7
= 38.67km/h
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Answered by
6
Answer:
S1=50km
V1=30km/h
t=distance/time
=50/30=5/3h
S2=40km/h
V2=60km/h
time taken =distance /time
=40/60
=2/3h
avg. speed =total time /total time taken
=(50+40)÷(5/3)+(2/3)
90÷(7/3)
270/7=38.67km/h
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