A car travels from A to B at 60 km/hr and returns to A at 90 km/hr. What is its average velocity and Average speed?
Answers
Answer:
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Step-by-step explanation:
First lets start with the simple One -
Velocity - Velocity is speed with Direction or in another words Displacement by time taken. So if a vehicle starts at A and Ends back at point A then the displacement is 0 hence the velocity is 0.
Speed - Assuming the distance between A to B while going from A to B is x kms
Case 1 - The Car goes returns from B to A via the same exact route it went from A to B. So the Average Speed will be total distance travelled by total time taken so .
Total Distance = x + x = 2x
Total Time = x/60 hrs + x/90 hrs = 3X+2X/180 = 5X/180
Average Speed = 2X*180/5X = 360/5 = 72km/hr
Case 2 - The Card goes to A to B via route 1 and returns back via Route 2 so one of the distances is X and the return distance is Y.
so now Average Speed = ((X+Y)/(3X+2Y)) *180
So in Case 2 if you substitute X = Y then also you get 2/5 * 180 = 72 Km / hr.
Answer:
Average speed: 72 km/h
Average velocity: 0
Step-by-step explanation:
Average speed:
Let the distance travell d from A to A to B= x/60
Time taken to travelto A = x/90
total time taken = x/60+x/90
Total distance travelled = 2x
Average speed = total distance travelled/ total time taken
= 2x/x/60+x/90
= 2×60×90/60+90
Average speed = 72 km/h
Average velocity:
Displacement from A to B = x
Total displacement = 0
Total time taken = x/60+x/90
Average velocity = Total displacement/total time taken
= 0/x/60+x/90
Average velocity = 0