A car travels from A to B at a speed of 20 kmh–1 and returns at a speed of 40 kmh–1. The average velocity of the car for the whole journey is
Answers
Answered by
0
This question is very simple.
Average speed = Total Distance / Total Time Taken
But we have only speeds S1 and S2
S1 = 40 km/hr
S2 = 60 km/hr
So now let us assume that the distance between a and b will be 120 km ( LCM of 40 and 60 )
D1 = 120 km
D2 = 120 km
Total Distance = D1 + D2 = 120 + 120 = 240 km
Now
T1 = D1/S1
T1 = 120/40 = 3 hr
T2 = D2/S2
T2 = 120/60 = 2 hr
Total Time = T1 + T2 = 3 + 2 = 5 hr
Now
Average Speed = Total Distance / Total Time = 240 / 5
Average Speed = 48 km/hr
Edit: 28 July 2017
You can also solve this que using a simple formula
Avg Speed = 2xy/x+y
x = 40 and y = 60
Avg Speed = 2 x 40 x 60/100
Avg Speed = 48 km/h
Average speed = Total Distance / Total Time Taken
But we have only speeds S1 and S2
S1 = 40 km/hr
S2 = 60 km/hr
So now let us assume that the distance between a and b will be 120 km ( LCM of 40 and 60 )
D1 = 120 km
D2 = 120 km
Total Distance = D1 + D2 = 120 + 120 = 240 km
Now
T1 = D1/S1
T1 = 120/40 = 3 hr
T2 = D2/S2
T2 = 120/60 = 2 hr
Total Time = T1 + T2 = 3 + 2 = 5 hr
Now
Average Speed = Total Distance / Total Time = 240 / 5
Average Speed = 48 km/hr
Edit: 28 July 2017
You can also solve this que using a simple formula
Avg Speed = 2xy/x+y
x = 40 and y = 60
Avg Speed = 2 x 40 x 60/100
Avg Speed = 48 km/h
Answered by
1
In the question Average Velocity is asked
Avg. Velocity = Total Displacment / Total Time
∵ Car goes from A⇒B then B⇒A Displacement = 0
∴ Average Velocity = 0 kmh⁻¹
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