Question

A car, travels from stop A to stop B with
a speed of 30 km/h and then returns to back back to A with a speed of 50 km/h. Find.
displacement of the car.
distance travelled by the ear.​

Answer 1

SoluTion:

Given :

• A car travels from stop A to stop B with a speed of 30 km/h and then returns back to stop A with a speed of 50 km/h.

To find :

• Displacement and distance

Explanation :

We know that, Displacement is the shortest path covered by an object. It can be zero when object comes back to its initial position. In this case, car comes to Stop A after covering some distance. Hence, we can say that Displacement is zero.

Now, we've to find the distance. For finding distance, we've to find average speed.

There are two cases :

First, When car travels from stop A to B and second when car comes back to A after covering some distance.

Let distance covered in both cases be x km.

So, total distance = 2x km

Now, time taken in 1st case :

$\boxed{\sf{Time\:=\:\dfrac{Distance}{Speed}}}$

→ Time = $\sf{\dfrac{x}{30}}$

Similarly, time in second case :

→ Time = $\sf{\dfrac{x}{50}}$

→ Total time = $\sf{\dfrac{4x}{75}}$ h

$\large{\boxed{\red{\sf{Speed_{Av}\:=\:\dfrac{Total\:distance}{Total\:time}}}}}$

Putting the values, we get,

→ Average speed = 37.5 km/h

Hence, distance = 2x → 2 × 37.5 = 75 km

Answer 2

Step-by-step explanation:

As we Have Given ,

Car Travels From A to B with a Speed 30km/hr

Speed From A to B = 30km / hr

Returns Back To The Point A , it Means Speed of Car From B to A = 50km/ hr

Displacement is The Shortest Distance Covered By Object..