A car travels from stop A to stop B
with a speed of 30 km /h and then returns
back to A with a speed of 50 km/h find.
1- displacement of the car
2- distance travelled by the car
3- average speed of the car
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Answer:
1. dispalcement of car = 0
2. average speed = 37.5kmph
Explanation:
Case1: when car travel from A to B
speed v1 = 30kmph
let distance d1 = x
=> time t1 = x/30 h
Case2: when car return back
speed v2 = 50kmph
distance d2 = x
=> time t2 = x/50 h
Now, total time T = x/50 + x/30 = 4x/75 h
total distance D = 2x
•°• average speed of car = D/T
= 2x/(4x/75) = 37.5 km/h
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