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Step-by-step explanation:
1.] Given : ΔABC AB is the greatest side
So, AB > BC and AB > AC
We know that the angle opposite to the greatest is also the greatest one
So, ∠C > ∠A → (1) and ∠C > ∠B → (2)
Adding the equation (1) and (2)
⇒2∠C > ∠A + ∠B
Adding ∠C on both sides
⇒3∠C > ∠A + ∠B + ∠C
⇒3∠C > 180° [ ∵ Sum of the angle in triangle = 180° ]
∴ ∠C > 60°
2.]
Given, E is mid point of AD
Also EB∥DF
⇒ B is mid point of AF [mid--point theorem]
so, AF=2AB (1)
Since, ABCD is a parallelogram,
CD=AB
⇒AF=2CD
AD∥BC⇒LB∥AD
In ΔFDA
⇒LB∥AD
⇒
LD
LF
=
AB
FB
=1 from (1)
⇒LF=LD
so, DF=2DL
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