Question

If Sin A = 3/4, Calculate cos A and tan A..​

Answer 1

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Solution:

Let us say, ABC is a right-angled triangle, right-angled at B.

Sin A = 3/4

As we know,

Sin A = Opposite Side/Hypotenuse Side = 3/4

Now, let BC be 3k and AC will be 4k.

where k is the positive real number.

As per the Pythagoras theorem, we know;

Hypotenuse² = Perpendicular²+Base²

AC² = AB² + BC²

Substitute the value of AC and BC in the above expression to get;

(4k)² = (AB)² + (3k)²

16k² – 9k² = AB²

AB² = 7k²

Hence, AB = √7 k

Now, as per the question, we need to find the value of cos A and tan A.

cos A = Adjacent Side/Hypotenuse side = AB/AC

cos A = √7 k/4k = √7/4

And,

tan A = Opposite side/Adjacent side = BC/AB

tan A = 3k/√7 k = 3/√7

Answer 2

Answer:

Step-by-step explanation:

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