A car travels from stop A to stop B with a speed of 30 km/hr and then returns
back to A with a speed of 50km/hr. Find :
i) Displacement of the car
ii) Distance travelled by the car
iii) Average speed of the car
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Answer:
Explanation:
Speed of the car from stop A to stop B = 30km/hr
Speed of the car from stop B to stop A = 50km/hr
Let the distance from A to B = x
Displacement of the car when it comes back to the same position = 0.
Distance travelled = 2x.
Time taken by the car when it moves from A to B is given by
t1 = Distance/Speed = x/30
Time taken by the car when it moves from B to A,
t2 = Distance/Speed = x/50
Total time
= t1 + t2
= x/30 + x/50
= (5x + 3x)/150
= 8x/150
Average speed = Total distance/Total time
= 2x/(8x/150)
= 37.5 km/hr
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