Question

A car travels from stop A to stop B with a speed of 30 km/hr and then returns
back to A with a speed of 50km/hr. Find :
i) Displacement of the car
ii) Distance travelled by the car
iii) Average speed of the car​

Answer 1

Answer:

Explanation:

Speed of the car from stop A to stop B = 30km/hr

Speed of the car from stop B to stop A = 50km/hr

Let the distance from A to B = x

Displacement of the car when it comes back to the same position = 0.

Distance travelled = 2x.

Time taken by the car when it moves from A to B is given by

t1 = Distance/Speed = x/30

Time taken by the car when it moves from B to A,

t2 = Distance/Speed = x/50

Total time

= t1 + t2

= x/30 + x/50

= (5x + 3x)/150

= 8x/150

Average speed = Total distance/Total time

= 2x/(8x/150)

= 37.5 km/hr