Question

A car travels from stop A to stop B with a speed of 36 km/h and then returns back to A with a speed of 54 km/h. Find :
(i) displacement of the car (ii) average speed of the car​

Answer 1

Answer:

displacement = 0

let distance x than total

distance

Step-by-step explanation:

2x Tim ein I condition

x/36 h

I I

time x/54

than total

time

x/36+x/54

5x/108

than average speed

2x/5x/108

d /t

43.20 km /h ok

bro

Answer 2

Answer:

• Displacement of the car = 0
• Average speed of the car = 43.20 km/hr

Step-by-step explanation:

We have been given that a car travels from stop A to stop B with a speed of 36 km/h and then returns back to A with a speed of 54 km/h.

• Speed of Car at Stop A = 36 km/hr
• Speed of Car at Stop B = 54 km/hr

We have to find the displacement of the car.

• Displacement of the car is 'ZERO' because the initial position and final position of car is same.

Now, we have to find the average speed of the car.

• Let the distance travelled by car be x. Since car travelled two times( A to B & B to A), so total distance will be 2x.

Find the time taken by car to cover the distance from stop A to stop B:

• Time A = x/36 hr

Find the time taken by car to cover the distance from stop B to stop A :

• Time B = x/54 hr

Find the total time taken by car to cover the distance:

• Total Time = x/36 + x/54
• Total Time = 5x/108

Find the average speed of the car: Average Speed = Total Distance/Total Time

Average Speed = 2x/ 5x/108

Average Speed = 2x/5x × 108

Average Speed = (108 × 2)/5

Average Speed = 43.20 km/hr