Question

A car travels from stop A to stop B with a speed of 50km/h and then return back to A with a speed of 60km/h . Find i) displacement of the car, ii) distance Travelled by the car, iii) average speed of the car​

Answer 1

Answer:

$\boxed{\textbf{\large{displacement=0 km}}}$

$\boxed{\textbf{\large{Average speed = 54.54 km/hr}}}$

$\boxed{\textbf{\large{total distance = 3.92 km}}}$

Explanation

A car travels from A to B with a speed 50km/hr

Return back to point A with a speed of 60km/hr

☑ here displacement is Zero,

cause displacement is shortest distance between initial and final point

$\boxed{\textbf{\large{displacement=0 km}}}$

☑ To calculate the distance travelled by a car, we have to know speed and time, but there is no time mention in the question,

so, take variable m is a as distance

distance = m

car travels a distance from A to B and then return back to A therefore take a distance 2m

total distance = 2m

let's find time,

we know,

speed = distance /time

☑ the time taken to the car from A to B =time = distance /speed

time = m / 50

☑ from B to A speed of the car is 60km/hr

time = m /60

so, total time =[ m / 50 + m / 60 ]

= [11m /300 ] hr

therefore Now,

☑ Average speed

Average speed = total distance / total time

= 2m / [11m /300]

=2m x ( 300 /11m)

=54.54 km /hr

$\boxed{\textbf{\large{Average speed = 54.54 km/hr}}}$

☑ total distance

total distance =total time X speed

2m= [11m/300] X 54.54

m= 1.96

therefor,

total distance = 2m = 2 X 1.96

= 3.92 km

$\boxed{\textbf{\large{total distance = 3.92 km}}}$