a car travels half of the dostamce with constant velocity 40km/hr and another half with a constant velocity 60km/hr along a straight line.the average velocity of the car is
insaneadmirer:
40+60/2
Answers
Answered by
2
Hey Mate,☺️☺️
Here is your answer,☺️☺️
HOPE IT HELPS YOU A LOT IN YOUR FUTURE☺️
Thank you friend ☺️☺️
Here is your answer,☺️☺️
HOPE IT HELPS YOU A LOT IN YOUR FUTURE☺️
Thank you friend ☺️☺️
Attachments:
Answered by
1
HEY !! GOOD MORNING !! HERE'S YOUR ANSWER
Let the total distance covered by the car be 100km.
we have,
hslf of the total distance = 100/2 = 50km
Speed while travelling the 1st half km = 40km/hr
so time taken to travel the 1st half km = 50km/ (40km/hr) = 5/4 hr
also, Distance covered in the 2nd half kilometres = 100/2 km = 50 km
Speed of the car while travelling the 2nd half km = 60 km/hr
so, time taken by the car to travel the 2nd half kilometres = 50km / (60km/hr) = 5/6 hr
we know that, average velocity = total distance covered / total time taken
= 100/ (5/4+ 5/6) km/hr
= 100/(25/12) km/h
= 48 km/ h
Hence, average velocity of the car is 48 km/h..
HOPE THIS HELPS U
HAVE A GREAT DAY
Let the total distance covered by the car be 100km.
we have,
hslf of the total distance = 100/2 = 50km
Speed while travelling the 1st half km = 40km/hr
so time taken to travel the 1st half km = 50km/ (40km/hr) = 5/4 hr
also, Distance covered in the 2nd half kilometres = 100/2 km = 50 km
Speed of the car while travelling the 2nd half km = 60 km/hr
so, time taken by the car to travel the 2nd half kilometres = 50km / (60km/hr) = 5/6 hr
we know that, average velocity = total distance covered / total time taken
= 100/ (5/4+ 5/6) km/hr
= 100/(25/12) km/h
= 48 km/ h
Hence, average velocity of the car is 48 km/h..
HOPE THIS HELPS U
HAVE A GREAT DAY
Similar questions