A car travels on a horizontal circular track of radius 9 m, starting from rest at a constant tangential acceleration of 3 m/s2. what is the resultant acceleration of the car, 2 sec after starting
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Hello! let me answer this with some simplified steps.Since,
tangential acceleration=3m/s^2=dv/dt
integrate to get,
3dt=dv
V=6m/s
& so, centripetal acceleration=v^2/r=4m/s^2
net acceleration=√ac^2+at^2
=√25=> 5m/s^2
tangential acceleration=3m/s^2=dv/dt
integrate to get,
3dt=dv
V=6m/s
& so, centripetal acceleration=v^2/r=4m/s^2
net acceleration=√ac^2+at^2
=√25=> 5m/s^2
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