A car travels with a constant velocity of 27 km/ h for 10min and then decelerates for 10 mins before Coming to rest . Find the total distance travelled by the car.
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It's a question of Physics Class 9
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Answer:
6.75 m
Explanation:
27km/h
=27×1000/60×60
=7.5m/s
car travel in minutes =10×60×7.5=4500m=4.5km
- u=7.5,
- t=10×60=600s
- v=0
by formula v=u + at
a=-u/t
a=-0.0124m/s^2
now v^2=u^2+2as
it gives s=u^2/2a
s=2250m=2.25 km
total distance=4.5+2.25=6.75
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