Question

a car travels with a speed of 30 kmh^-1 for 30 minute and then the speed with 40 kmh^-1 for one hour. find the total distance travelled by the car​

Answer 1

Answer:

$\orange{ \boxed{ \sf \: total \: distance \: \: S = 55 \: km}}$

Explanation:

Given,

Case :1

$\sf \: veocity \: \: v_1 = 40 \: km {h}^{ - 1} \\ \sf \: time \: t_1 = 30 \: min \: = \frac{30}{60} \: h = 0.5 \: h$

Case :2

$\sf \: velocity \: v_2 = 40 \: km {h}^{ - 1} \\ \sf \: time \: t_2 = 1 \: h$

To find :

Total distance S

Solution :

Finding distance for → case :1

$\sf \: s_1 = v_1 \times t_1 \\ \sf \: \: \: \: \: = 30 \times 0.5 \\ \: \: \: \: \: \sf= 15 \: km$

Finding distance for → case : 2

$\sf \: s_2 = v_2 \times t_2 \\ \: \: \: \: \: \: = 40 \times 1 \\ \: \: \: \: \: \: \sf = 40 \: km$

So total distance,

$\sf \: S = s_1 + s_2 \\ \: \: \: \: = 15 + 40 \\ \: \: \: \: = 55 \: km$