A car travels with a uniform velocity of 20 m/s for 5 s. The brakes are then applied and the car is uniformly retarded. It comes to rest in next 8 s. A velocity – time graph for the above motion is given below. Use the graph to find the answers of the following questions:-
What is the acceleration caused by the car represented by section AB of the given graph?
a. 4 m/s2
b. 0.25 m/s2
c. 0
d. 2 m/s2
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Initial Velocity = 20 m/sec
Time = 5 seconds.
After 5 seconds
Initial velocity = 20 m/sec
Final velocity = 0m/sec
Time = 8seconds
(i) Distance covered in first 5 seconds
Since Body moved with uniform motion, this means that acceleration =0
So, From 2nd equation of motion :-
(ii) Distance covered after breaks are applied :-
U= 20 m/sec
V = 0 m/sec
T = 8 second
So,
v = u + at
a = v - u / t
a = -20/8
= - 2.5
So,
s = v^2 - u^2/2a
s = -20^2/-5
s = 80 m
(iii) Total Distance travelled
100 + 80 = 180 m
(iv) Acceleration during 1st 5 seconds = 0m/sec²
Acceleration during last 8 seconds = (-2.5)m/sec²
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