a car travels with uniform velocity of 20m/s for 5s.then the brakes are applied further the car comes to rest after 8s. Use graph to find
a)the distance traveled in 5s.
b)the distance travelled after applying brakes.
c)total distance travelled.
d)find the acceleration during 5s and last 8s.
Please ans fast
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Answer:-
Initial Velocity = 20 m/sec
Time = 5 seconds.
After 5 seconds
Initial velocity = 20 m/sec
Final velocity = 0m/sec
Time = 8seconds
(i) Distance covered in first 5 seconds
Since Body moved with uniform motion, this means that acceleration =0
So,From 2nd equation of motion :-
S = ut + 1/2 at^2
s = at ( a = 0)
s = 20 × 5
s = 100
(ii) Distance covered after breaks are applied :-
U= 20 m/sec
V = 0 m/sec
T = 8 second
So,
v = u + at
a = (v - u)/t
a = -20/8
a = -5/2
a= -2.5
(iii) Total Distance travelled=
100 + 80
180m.
iv) Acceleration during 1st 5 seconds = 0m/sec²
Acceleration during last 8 seconds = (-2.5)m/sec²
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