A car was moving with a velocity of 90 km/h. the driver applies brake and the car
comes to rest after traveling 400m. What is the acceleration of the car and the time
taken by the car to come to rest?
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Velocity of moving vehicle=v
0
and decceleration =a
Final velocity of the vehicale =0 (As it stops)
Let the stopping distance be s
Then applying the third equation of motion we have:
v
2
=v
0
2
+2(−a)s
⇒0=v
0
2
−2as
⇒s=
2a
v
0
2
→ Expression for stopping distance.
0
and decceleration =a
Final velocity of the vehicale =0 (As it stops)
Let the stopping distance be s
Then applying the third equation of motion we have:
v
2
=v
0
2
+2(−a)s
⇒0=v
0
2
−2as
⇒s=
2a
v
0
2
→ Expression for stopping distance.
Answered by
0
Explanation:
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