Question

A car weighing 10.000 N on a hill which makes an angle of 20°with the horizontal.find the components of car's weight parallel and perpendicular to the road.

Answer 1

The parallel component of the cars weight will be mgsin∅. While the perpendicular component of the car's weight would be mgcos∅.

mgsin∅ = 10000sin20°

mgcos∅ = 10000cos20°

Answer 2

Given :

Weight of car , W = 10000 N .

Angle make by car on hill , $\theta=20^{\circ}$ .

To Find :

The components of car's weight parallel and perpendicular to the road.

Solution :

We know , parallel component is given by :

$F_p=W\sin\ \theta\\\\F_p=10000\times \sin\ 20^o\\\\F_p=3420.2\ N$

Also , perpendicular component is given by :

$F_{per}=W\cos\ \theta\\\\F_{per}=10000\times\cos\ 20^o\\\\F_{per}=9396.9\ N$

Therefore , the components of car's weight parallel and perpendicular to the road is 3420.2 N and 9396.9 N respectively .

Learn More :

Kinematics

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