A car weighing 100kg is on a slope that makes an angle 30 with the horizontal.the component of cars weight parallel to the slope is(g=10ms-2
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Answer:
50 Kg
Explanation:
Along the parallel of the slope, the car weighs equal to MgSin30°
= 100 Kg * 1/2 (Value of Sin30°= 1/2)
= 50 Kg
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