Question

A car weighing 100kg is on a slope that makes an angle 30 with the horizontal.The component of cars weight parallel to the slope is(g=10m/s^2)

Answer 1

see the diagram.

weight = m g = 100 * 10 = 1,000 N
component along the slope = mg sin 30° = 1000*1/2 = 500 N

Answer 2

Answer:

500N

Explanation:

mass=100kg

g=10ms

F=mg

100×10=1000

so, component of car's weight parallel to slope = Fsin30

1000×1/2=500N