Prove that 1/3-√8 -1/√8-√7 +1/√7-√6 -1/√6-√5 +1/√5-2=5
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Answered by
429
1/3-√8-1/√8-√7+1/√7-√6-1/√6-√5+1/√5-2=5
Now,
1/3-√8 = 3+√8,
1/√8-√7 = √8+√7,
1/√7-√6 = √7+√6,
1/√6-√5 = √6+√5,
1/√5-2 = √5+2
∴ 1/3-√8-1/√8-√7+1/√7-√6-1/√6-√5+1/√5-2
= 3+√8-√8-√7+√7+√6-√6-√5+√5+2
=3+2 = 5
Hence proved.
Now,
1/3-√8 = 3+√8,
1/√8-√7 = √8+√7,
1/√7-√6 = √7+√6,
1/√6-√5 = √6+√5,
1/√5-2 = √5+2
∴ 1/3-√8-1/√8-√7+1/√7-√6-1/√6-√5+1/√5-2
= 3+√8-√8-√7+√7+√6-√6-√5+√5+2
=3+2 = 5
Hence proved.
Answered by
34
1/3-√8-1/√8-√7+1/√7-√6-1/√6-√5+1/√5-2=5
Now,
1/3-√8 = 3+√8,
1/√8-√7 = √8+√7,
1/√7-√6 = √7+√6,
1/√6-√5 = √6+√5,
1/√5-2 = √5+2
∴ 1/3-√8-1/√8-√7+1/√7-√6-1/√6-√5+1/√5-2
= 3+√8-√8-√7+√7+√6-√6-√5+√5+2
=3+2 = 5
Hence proved.
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