Question

A car weighing 1120kg is going up an incline of 1 in 56 at the rate of 20m in 2s find the power of the engine if frictional force is 64n

Answer 1

Given conditions ⇒

Mass = 1120 kg.

Sin θ = 1/56

Velocity = 20/2 = 10 m/s.

Now, we know that For an incline,

Force = mgsinθ + friction.

⇒ Force = 1120 × 10 × 1/56 + 64

⇒ Force = 264 N.

Now, We know, Power = Force x Velocity.

∴ Power = 264 × 10 = 2640 W.

Hope it helps.

Answer 2

Force = mgsinθ + friction.

⇒ Force = 1120 × 10 × 1/56 + 64

⇒ Force = 264 N.

Now, We know, Power = Force x Velocity.

∴ Power = 264 × 10 = 2640 W.