Question

A capacitor having capacitance of 5uf is charged to a voltage of 10v.Calculate the stored energy in joules

Answer 1

Capacitance of the capacitor = 5 μF

Capacitance = $5 \times 10^-^6$ F

Voltage applied across the capacitor = 10 V

The capacitor will get charged and store electrical energy.

$Energy = \frac{1}{2} \times C \times V^2$

$Energy = \frac{1}{2} \times 5 \times 10^-^6 \times 10 \times 10$

$Energy = 2.5 \times 10^-^4 J$

Hence, the energy stored in the capacitor is: $2.5 \times 10^-^4 J$

Answer 2

Answer:

A capacitor having a capacitance of 5uf is charged to a voltage of 10v, the stored energy in the capacitor is $U=2.5*10^{-4}J$

Explanation:

• A capacitor is used to store charge

• The electrical potential energy is stored in a capacitor

• For a capacitor with capacitance (C) and potential difference across the battery (V), the energy stored is

        $U=\frac{1}{2}CV^{2}$

From the question, we have

the voltage across the battery $V=10v$

the capacitance of the capacitor    $C=5*10^{-6}F$

put the values given,

the energy stored in the capacitor is

$U=\frac{1}{2}*5*10^{-6} *(10^{2} )$

⇒  $U=2.5*10^{-4}J$