Question

A car weighing 1500kg moving with a velocity of 60 km/hr retards uniformly to come to rest in 20 sec. Find the change in momentum in 1 sec.

Answer 1

u = 60km/h = 50/3 m/s
v = 0
t = 20 s
v =u +at = 0
》0=50/3 +20a
》a= -5/6
Now force, F = ma = 1500 × (-5)/6
= -1250 N
F = change in momentum / time
》-1250 = change in momentum/ 1
》change in momentum= -1250kgm/s

Answer 2

Answer:

-1250.2N

Explanation:

Given:

m=1500kg

u=60km/h

$=\frac{(60)(1000m)}{(60)(60s)} =16.67m/s$

v=0km/h=0m/s

t= 20s

To find :

Change in momentum

Solution:

The body's momentum is created by multiplying its mass and speed. Momentum is described as follows: p= mv

The impulse and the rate of momentum change are the same. The relationship between impulse and momentum is explained by the impulse-momentum theorem. The equation p= describes the change in momentum (mv)

Momentum can fluctuate as a result of a change in the body's mass or velocity.

The quantity of momentum that changes in a second is the rate of change of momentum.

rate of momentum change = $\frac{TotalChangeInMomentum}{TimeTaken}$

=$\frac{FinalMomentum-InitialMomentum}{TimeTaken}$

$=\frac{mv-mu}{t} \\=\frac{m(v-u)}{t}\\=\frac{1500kg(0m/s-16.67m/s)}{20s}$

= -1250.2N

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