Question

A car weighing 2400kg and moving with a velocity of 20m/s is stopped on 10seconds by applying breaks calculate total distance

Answer 1

u = 20m/s

v = 0 m/s

t = 10 sec

     first calculate aceleration 'a'

v = u +at

therefore.... a = - 2m /s2

    now calculate distance S

v2 - u2 = 2aS

0  - 400 = 2 (-2)S

S = 100m...

   hope u get that right

Answer 2

Answer:

Explanation:

mass(m)= 2400 kg,       initial velocity(u)- 20m/s,   final velocity(v) =0     time taken(t)= 10s         retardation= ?     force=?

we can say thar retardation is negative acceleration

(i)by using first equation of motion,we get

v=u +at

0= 20+aX10

0= 20+10a

-20 = 10a

-20/10= a

-2= a

thus, retardation= 2m/s2

(ii) f= ma

f= 2400 X (-2)

= -4800N

thumbs up plz!!!