Question

A car weighs 1800 kg. The distance between its front and back axles is 1.8 m. Its centre of gravity is 1.05 m behind the front axle. Determine the force exerted by the level ground on each front wheel and each back wheel.

Answer 1

Hii friend,

◆ Answer-
F1 = 7500 N
F2 = 10500 N

◆ Explaination-
● Given -
m = 1800 kg
D = 1.8 m
d = 1.05 m

● Solution-
If F1 and F2 are forces on front wheels and back wheels respectively.

For rotational equilibrium, torque is conserved.
F1×d = F2×(D-d)
F1×1.05 = F2×(1.8-1.05)
F2 = 7/5 F1

But total force will be
F = mg
F1 + F2 = 1800×10
F1 + 7/5 F1 = 18000
F1 = 18000×5/12
F1 = 7500 N

Also,
F2 = 7/5 F1
F2 = 7/5 × 7500
F2 = 10500 N

Thus, Force beared on front wheels 7500 N and back wheels 10500 N.

Hope that is useful..