Find the moment of inertia of a sphere about its tangent to the sphere, given the moment of inertia of the sphere about any of the diameters to be 2MR²/5, where M is the mass of the sphere and R is the radius of the sphere.
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Hey buddy,
◆ Answer- 7/5 MR^2
◆ Explaination-
# Given-
M.I. of sphere through diameter = 2/5 MR^2
# Solution-
According to parallel axis theorem, the M.I. about a tangent of the sphere will be
I' = I + MR^2
I' = 2/5 MR^2 + MR^2
I' = 7/5 MR^2
The M.I. about a tangent of the sphere will be 7/5 MR^2.
Hope that helps you...
◆ Answer- 7/5 MR^2
◆ Explaination-
# Given-
M.I. of sphere through diameter = 2/5 MR^2
# Solution-
According to parallel axis theorem, the M.I. about a tangent of the sphere will be
I' = I + MR^2
I' = 2/5 MR^2 + MR^2
I' = 7/5 MR^2
The M.I. about a tangent of the sphere will be 7/5 MR^2.
Hope that helps you...
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