Physics, asked by surajchauhan15f, 1 year ago

A car weighting 4000 kg travelling of 25 km/sec stops in 5 sec by deceleration uniformly, then its retardation is?

Answers

Answered by SKairon
10
u=25 km/s
t=5 s
v=0
v=u+at
0=25+5a
-25=5a
a= -5 km / s^2

Retardation = -a = 5 km / s^2
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