A car weighting 4000kg travelling of 25 km/sec stops in 5 sec by decelerating unifrmly then its retardation is
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2
According to question
Mass of car m = 400 Kg
velocity v = 25 Km/sec = 25 * 3600 Km/hr
time t = 5 sec = 5 / 3600 hr
retardation
r = a = 25 * 3600 / 5 / 3600 = 5 m/ sec^2
thus the retardation is 5 m/ sec^2
Mass of car m = 400 Kg
velocity v = 25 Km/sec = 25 * 3600 Km/hr
time t = 5 sec = 5 / 3600 hr
retardation
r = a = 25 * 3600 / 5 / 3600 = 5 m/ sec^2
thus the retardation is 5 m/ sec^2
Answered by
2
Given:
mass = m=4000kg
initial velocity=u =25km/sec =25×1000m/ sec
time = t=5 sec
final velocity = v=0 m/s
acceleration = a= v-u/ t
=0-25000//5
=-5000 m/s2
Therefore retardation= 5000m/s2
mass = m=4000kg
initial velocity=u =25km/sec =25×1000m/ sec
time = t=5 sec
final velocity = v=0 m/s
acceleration = a= v-u/ t
=0-25000//5
=-5000 m/s2
Therefore retardation= 5000m/s2
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