Physics, asked by TheLifeRacer, 1 year ago

A car weighting 600kg travels with 72km/h stops at a distance 50m de-acceleration uniformly , the force exerted by the braks will be ?

Answers

Answered by sujeetgupta1
0
mass of car=600 kg

initial velocity u = 72km/h

distance s= 50m

final velocity v=0    (car stop)

By equation of motion

Vsq. =Usq. +2as
0sq.=72sq.+2×a×50
a=5184/-100
a=-51.84m/s^2

after this

F=600×(-51.84)=-31104

thus,force exerted by break will be 31104N.


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