what happens when sodium hydroxide (excess) treated with zn(oh)2
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double displacement will be there
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zn{oh}2 +naoh------ na2{zn{oh}4}
it reacts to form tetrahydroxozincate{II} solution
it also forms a white precipitate
it reacts to form tetrahydroxozincate{II} solution
it also forms a white precipitate
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