Question

a car which costs rs 2,50,000 depriciates by 10% every year. what will the car be worth after 3 years

Answer 1

(250000 ×10×3)/100
=75000rupee depreciate
250000-75000
=175000rupee

Answer 2

Solution :
   Here,
              Initial cost of car (P) = Rs. 2,50,000
              Rate of depreciation per year (R) = 10 %
             Number of year the car is depreciated (T) = 3 years
  Now, 
             Cost of car after 3 years (A) = P×[1-(R/100)]^T
                                                          = 250000×[1-(10/100)]^3
                                                          = 182250
Hence, the car will be worth Rs. 182250 after 3 years.