Question

A car with an initial velocity of 24.5 m/s east has an acceleration of 4.2 m/s² west. What is its displacement at the moment that its velocity is 18.3 m/s east?

Answer 1

This is the answer.

Answer 2

Answer:

x = -31.59 meters

Explanation:

Initial velocity of the car, u = 24.5 m/s

Acceleration of the car, $a=4.2\ m/s^2$

Final velocity of the car, v = 18.3 m/s

Let x is the displacement of the car at this moment. It can be calculated using third equation of motion as :

$x=\dfrac{v^2-u^2}{2a}$

$x=\dfrac{(18.3)^2-(24.5)^2}{2\times 4.2}$

x = -31.59 meters

So, the displacement of the car at that moment is 31.59 meters. Hence, this is required solution.