a carb is retarted by applying brakes at the rate of 5m/s square and isnstopped after 5 secs. Find the initial velocity
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Answered by
1
v=0
a= -5m/s square
t=5sec
so v=u+at first eq of motion
0=u+-5×5
0=u-25
u=25m/s
a= -5m/s square
t=5sec
so v=u+at first eq of motion
0=u+-5×5
0=u-25
u=25m/s
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Answered by
1
V=u+at
0=u+(-5)×5
25=u
25m/s
Hope it helps u
Thanks
0=u+(-5)×5
25=u
25m/s
Hope it helps u
Thanks
bye
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