Question

A carbon compound on analysis gave the following percentage composition ,carbon14.5%,Hydrogen 1.8%,chlorine 64.46% and oxygen 1o.24% Find the empirical formula of the compound​

Answer 1

Answer:

the empirical formula of the compound​   C₄H₆Cl₆O₅

Explanation:

the empirical formula of the compound​ H₂₄Cl₃O₂

Given

C = 14.5 %

H = 1.8 %

Cl = 64.46 %

O = 24 %  

empirical formula = ??

Solution

first divide each with respective atomic mass

C                 H                        Cl                        O

14.5/12        1.8/1            64.46/35.5              24/16

1.20             1.8                     1.8                      1.5

divided by with lowest number

1.2/1.2       1.8/1.2               1.8/1.2                  1.5 /1.2  

1                 1.5                        1.5                      1.25

multiply with suitable number to convert them into whole number

 1 X 4         1.5  X 4            1.5  X 4               1.25  X 4

4                    6                          6                       5

the empirical formula of the compound​  

C₄H₆Cl₆O₅