Math, asked by rikrishnaiah, 11 months ago

tan+sec-1 /tan-sec+1=1+sin/cos

Answers

Answered by sujalagarwal0987

0

Answer:

LHS=tan+sec-(sec^2-tan^2)/tan -sec+1

=tan+sec-(sec+tan)(sec+tan)/tan-sec+1

=tan+sec(1-sec+tan)/(1-sec+tan)

=tan+sec

=sin/cos+1/cos

=sin+1/cos

=1+sin/co=RHS

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