Question

A carbon compound on analysis gave the following percentage composition , carbon 14.5%, Hydrogen 1.8%, Chlorine 64.46% and Oxygen 19.24% . Find the empirical formula of the compound​

Answer 1

Answer:

Step 1: Percentage composition of the elements present in the compound. Step 2: Dividing by the respective atomic weights Step 3: Dividing the values in step 2 among them by the smallest number. Step 4: Multiplication by a suitable integer to get whole number ratio. ∴ The simplest ratio of the atoms of different elements in the compound. C : H : Cl : O = 2 : 3 : 3 : 2 ∴ Empirical formula of the compound C2H3Cl3O2.

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Answer 2

Answer:

C:H:Cl:O=2:2:3:3

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