Question

Find the smallest number which when divided by 24, 40 and 25 leaves a remainder of 10 in each case

Answer 1

Answer:

610

Step-by-step explanation:

Lcm of 24, 40, 25 = 600

to get the remainder 10 in each case we add 10 to 600

therefore 610 is the lowest number which when divided by 24, 40 and 25 it leaves a remainder of 10 in each case

Answer 2

Answer:

Answer is 610

Step-by-step explanation:

First we have to take least common multiple (LCM) of 24,40,25.

LCM of 24, 40, 25 is 600.

ATQ,

least common multiple that will leaves remainder 10 in each case

so, we have to add 10 to 600

Answer is 610.