A card drawn at random from a well shuffled pack of 52 playing cards find the probability of getting neither a red card nor a queen
Answers
Answered by
2507
Hey there!
Total number of Outcome (Cards) = 52
First eliminate half the deck, so as to get rid of the red cards. This leaves,
1/2 × 52 = 26 Cards
However, two queens were already gotten rid of when all the red cards were removed, leaving only two black queens.
Thus, we take two black queens away from our remaining cards,
26 - 2 = 24
∴ Number of Favourable Outcomes = 24
P(getting neither a Red nor a Queen) = 24/52
= 6/13
HOPE IT HELPS ^_^
Total number of Outcome (Cards) = 52
First eliminate half the deck, so as to get rid of the red cards. This leaves,
1/2 × 52 = 26 Cards
However, two queens were already gotten rid of when all the red cards were removed, leaving only two black queens.
Thus, we take two black queens away from our remaining cards,
26 - 2 = 24
∴ Number of Favourable Outcomes = 24
P(getting neither a Red nor a Queen) = 24/52
= 6/13
HOPE IT HELPS ^_^
Answered by
1146
There are 26 red cards in a pack of cards.
There are 4 queen cards out of which, 2 are red cards and 2 are black cards. The 2 red queen cards are already included in the red cards. Therefore, total number of queens and red cards = 26+4-2 = 28 cards
The remaining cards are 52-28 = 24 cards
The event is of neither getting a red card, nor a queen.
Therefore, our event has 24 favourable cards.
Probability = event/sample space
= 24/52
= 6/13
Hope it helps
Please mark as Brainliest ☺
There are 4 queen cards out of which, 2 are red cards and 2 are black cards. The 2 red queen cards are already included in the red cards. Therefore, total number of queens and red cards = 26+4-2 = 28 cards
The remaining cards are 52-28 = 24 cards
The event is of neither getting a red card, nor a queen.
Therefore, our event has 24 favourable cards.
Probability = event/sample space
= 24/52
= 6/13
Hope it helps
Please mark as Brainliest ☺
Riya2172002bts:
Thanks
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