Question

A card is drawn at a random from a pack of well shuffled 52 playing cards .find the probability that the card drawn is .1 an ace 2 a spade
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Answer 1

Answer:

$p(getting \: an \: event) = \frac{no. \: of \: favourable \: outcomes}{total \: no. \: of \: outcomes}$

1. Getting an ace

=No. of ace in duke=13

Total cards=52

$p(getting \: an \: ace) = \frac{13}{52} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{1}{4}$

2. Getting a spade

No. of spade in duke=13

Total no. of cards=52

$p(getting \: a \: spade) = \frac{13}{52} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{1}{4}$

Step-by-step explanation:

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