Math, asked by suryansh7755, 1 year ago

A card is drawn at random find the probability yhat it is neither an ace nor a king

Answers

Answered by CrashAsh
3
Total cards are 52
no. of aces=4
no. of kings=4
52-(4+4)=52-8=44
p(e) =  \frac{44}{52}
 =  \frac{22}{26}  =  \frac{11}{13}

Answered by aaronjoezac
1
total outcomes = 52
possible outcomes= 44(subtract 4 aces and 4 kings)

P(getting a card other than king or ace)= 44/52= 11/13

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