A card is drawn at random from a pack of 52 cards.
Find the probability that the card drawn is
(i) black
(ii) red and a queen
(ii) neither heart nor a king
(iv) an ace, jack or a king
(v) '10' of diamonds
(vi) club or an ace.
solve it with step wise
Answers
Answer:
i)1/2
ii)29/52
iii)4/13
...
Answer:
i. 1/2
ii. 1/26
iii. 9/13
iv. 3/13
v. 1/52
vi. 4/13
Step-by-step explanation:
There are 52 cards in a pack of card. The card divided into 4 groups Hearts , Diamonds, Clubs & Hearts. the 'As' are Known as Ace. The 'Ks' are known as King. The 'Qs' are known as Queen. The 'Js' are known as Jack.
The Ace,King,Queen & Jack are known as Face Cards.
All the face cards are 4 in number.
i. Total number of black cards = 26
Total number of cards = 52
therefor probability of getting a black card = 26/52
= 1/2
ii. Total numbers of cards that are red and a queen = 2
Total numbers of cards = 52
therefor the probability of getting a card that is red and a queen is
= 2/52
= 1/26
iii. Numbers of cards other than a heart = 52 - 13
= 39
Number of number of cards that are king = 4
So, total numbers of cards that is neither a hearts or a king = 39 - 3.
= 36
[We are taking 3 king card because we have already removed a king
card when we deducted the heart cards from the pack.]
Total numbers of cards are = 52
Therefor probability of getting a card that is neither a heart or a king is
= 36/52
=9/13
iv. Total number of ace cards = 4
Total number of jack cards = 4
Total number of king cards = 4
Total number of cards = 52
Therefor probability of getting a card that is an ace, jack or a king
= (4+4+4)/52
= 12/52
= 3/13
v. Number of card that is '10' of diamonds is = 1
Total numbers of cards =52
Therefor probability of getting a card that is '10' of diamonds is = 1/52
vi. Numbers of club cards = 13
Number of ace cards = 4 [Exclude the ace of club while adding
the numbers together]
Total number of cards that is a club or an ace = 13+3
= 16
Total number of cards = 52
Therefor the probability of getting a card that is a club or an ace = 16/52
= 4/13