A card is drawn at random from a pack of 52 cards. Find the probability of drawing a card which is neither a spade not a king
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●In a pack of 52 cards, you have 13 spades(including one king) and remaining three kings from the remaining three suits.
✍so, P(card drawn is spades and king)
= (13 + 3)÷ 52 = 16/52
✍Therefore,
P(card drawn is neither spades nor king)
= 1 - 16/52 = 1 - 0.3 = 0.7✔
Answered by
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a pack of card contain 52 cards
: . n(S)=52
let
event A: driving a card which is neither a spade not a king
there are 13 spade in 52 cards
and also 4 kings
n(A)=13+4=17
P(A)=n(A)/n(S)
P(A)=17/52
: . n(S)=52
let
event A: driving a card which is neither a spade not a king
there are 13 spade in 52 cards
and also 4 kings
n(A)=13+4=17
P(A)=n(A)/n(S)
P(A)=17/52
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