Math, asked by dubaialiya2003, 1 year ago

a card is drawn at random from a well shuffled pack of 52 cards find the probability of getting neither a black card or nor a jack


Bharat9304: 28/52
Bharat9304: 24/52

Answers

Answered by neha7755
51
Total number of Outcome (Cards) = 52

First eliminate half the deck, so as to get rid of the red cards. This leaves,

1/2 × 52 = 26 Cards

However, two queens were already gotten rid of when all the red cards were removed, leaving only two black queens.
Thus, we take two black queens away from our remaining cards, 

26 - 2 = 24

∴ Number of Favourable Outcomes = 24

P(getting neither a Red nor a Queen) = 24/52

                                                            = 6/13
Answered by Anonymous
56

Answer :


The probability of not getting a black card nor a jack is 15/26.


Step-by-step explanation :


A deck of cards contain 52 cards. A deck contains 4 Queen, 4 King and 4 Jacks.


And the deck contains 4 ranks - clubs (♧), diamond (◇), spades (♤) and hearts (♡).


A deck contains 4 ace. Each one of different ranks. 1 of clubs, 1 of diamond, 1 of spade and 1 of hearts.


The 52 cards are divided into colours - 26 reds and 26 blacks.


So, the favourable outcome = 26 blacks + 4 jacks = 30 cards


Now, probability -


\implies \frac{Favourable\:outcome}{Total\:outcome}


\implies\frac{30}{52}


\implies\frac{15}{26}


neha7755: Isn't ur answer wrong
neha7755: @Its mystery girl
neha7755: Anyways i m giving u thanks
thirudeepak2003: It’s wrong
thirudeepak2003: U hv taken the neither ! Outcome
thirudeepak2003: The qstn is probability of neither getting black or jack
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