Question

a card is drawn from a pack of 52 cards find the probability of getting a king or a heart or a red card​

Answer 1

Answer:

here is ur answer

Step-by-step explanation:

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Answer 2

ANSWER

According to principle of exclusion and inclusion

P(k U H U R) = P(k) +P(H) +P(R) -P(K ^ H) -P(K ^ R)

-P(R ^ H) + P(K ^ H ^ R)

where "^" denotes the intersection sign

" U " denotes the Union sign

and

K means king card ( total 4 and 1 in heart)

H means heart card ( total 13 )

R means Red card ( total 26 )

on calculating

P(K) = 4/52

P(H) = 13/52

P(R) = 26/52

P(K ^ H) = 1/52 { as only one king of H }

P(K ^ R) = 2/52

P(R ^ H) = 13/52

P(K ^ H ^ R) = 1/52

now putting values

P(k U H U R) = 4+13+26-1-2-13+1 / 52

P(k U H U R) = 28/52

P(k U H U R) = 7/13