Question

a card is drawn from a pack of 52 cards find the probability of having a face card and black face card

Answer 1

hey mate here is your answer

n(s)=52

now for a face card

n(e)=12

so p(e)=n(e)/n(s)

=12/52

=3/13

now for black face card

n(e)=3

p(e)=n(e)/n(s)

=3/52

hope it will help you

mark me brainliest ✌✌

Answer 2

Answer:

$\text{P(a face cards)=}\frac{3}{13}$

$\text{P(a black face cards)}=\frac{3}{26}$

Step-by-step explanation:

Given that a card is drawn from a pack of 52 cards

we have to find the probability of having a face card and black face card.

Total number of cards i.e total outcomes are

n(t)=52

Now for a face card  

n(f)=12

∴ $P(\text{a face card})=\frac{\text{Favourable outcomes }}{\text{Total number of outcomes }}=\frac{12}{52}=\frac{3}{13}$

Now for black face card

n(B)=6

∴ $P(\text{a black face card})=\frac{\text{No. of black face cards }}{\text{Total number cards}}=\frac{6}{52}=\frac{3}{26}$