A Carnot engine has an efficiency of 30% When the temperature of the sink is 27°C find the temperature of the source
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Answer:
hello mate..
Explanation:
efficiency of the cycle is given as η=1−
T
1
T
2
. Here T
1
is the temperature of the source and T
2
is the temperature of the sink. The temperature of the sink is given as 27
o
C=300K. Thus we get 0.5=1−
T
1
300
or
T
1
=600K
= 372degree Celsius
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